Question

10 ^ (th) term for AP-5,-10,-15,..... is :-(A) -955 (B) 50 (C) -50 (D) 955​

Answer 1

C

Explanation:

The nth term of an AP is

`a_(n)` = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 5 and d = a₂ - a₁ = - 10 - (- 5) = - 10 + 5 = - 5 , then

a₁₀ = - 5 + (9 × - 5) = - 5 - 45 = - 50 → C