Question

g Consider a mass-spring system where the spring constant is 5 N/m and the mass on the spring is 0.5 kg. The mass is moved a distance of -0.9 m from its equilibrium position. How much work is done by the spring

Answer 1

The work done by the spring is 2.025 J

Step-by-step explanation:

Given;

mass on the spring, m = 0.5 kg

spring constant, k = 5 N/m

extension of the spring, x = 0.9 m

The work done by the spring is calculated as;

`W = (1)/(2) kx^2\\\\W = (1)/(2) * 5 * (0.9)^2\\\\W = 2.025 \ J`

Therefore, the work done by the spring is 2.025 J