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42 votes
42 votes
Many types of decorative lights are connected in parallel. If a set of lights is connected to a 110 V source and the filament of each bulb has a hot resistance of what is the currentthrough each bulb

User Qiz
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1 Answer

19 votes
19 votes

Answer:

i₀ = V / R_i

Step-by-step explanation:

For this exercise we use Ohm's law

V = i R

i = V / R

the equivalent resistance for


(1)/(R_(eq)) = ∑
(1)/(R_i)

if all the bulbs have the same resistance, there are N bulbs


(1)/( R_(eq)) = (N)/(R_i)

R_{eq} = R_i / N

we substitute

i = N V / Ri

where i is the total current that passes through the parallel, the current in a branch is

i₀ = i / N

i₀ = V / R_i

User Sport
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