Question

In the diagram, WZ=StartRoot 26 EndRoot.

On a coordinate plane, parallelogram W X Y Z is shown. Point W is at (negative 2, 4), point X is at (2, 4), point Y is at (1, negative 1), and point Z is at (negative 3, negative 1).

What is the perimeter of parallelogram WXYZ?

units
units
units
units

Answer 1

its D.

Explanation:

took test

Answer 2

`P = 8 + 2√(26)`

Explanation:

Given

`W = (-2, 4)`

`X = (2, 4)`

`Y = (1, -1)`

`Z = (-3,-1)`

Required

The perimeter

First, calculate the distance between each point using:

`d = \sqrt{(x_1 - x_2)^2 + (y_1 -y_2)^2`

So, we have:

`WX = √((-2- 2)^2 + (4-4)^2 ) =4`

`XY = √((2- 1)^2 + (4--1)^2 ) =√(26)`

`YZ = √((1- -3)^2 + (-1--1)^2 ) =4`

`ZW = √((-3--2)^2 + (-1-4)^2 ) =√(26)`

So, the perimeter (P) is:

`P = 4 + √(26) + 4 + √(26)`

`P = 8 + 2√(26)`