Answer:
![\boxed{\textsf{ \textbf{ Yes} , the given triangle is a right angled triangle .}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/1i1ycbhh3797t1xxlypzso653uosbf48gm.png)
Explanation:
We are given three sides of the triangle and we need to say that whether the triangle is right Angled triangle or not . The given side lenghts are 6 cm , 8 cm and 10 cm . ( Units not given in Question ) .
So , a triangle with its given sides will be a right angled triangle if it has a right angle . And the sum of squares of two smallest sides must be equal to the square of the longest side . ( According to Pythagoras Theorem ) .
Here two smallest sides are 8cm and 6cm .
And the largest side is 10 cm .
And here the sum of squares of 8cm and 6cm should be equal to the square of 10cm in order to Prove it a right angled triangle .
Since LHS = RHS hence the triangle is a right angled triangle .
Figure :-
![\setlength{\unitlength}{1 cm}\begin{picture}(12,8)\thicklines \put(0,0){\line(1,0){4.49}}\put(0,0.01){\line(0,1){3}}\put(0,3){\line(3,-2){4.44}}\put(4.9,-0.3){\sf C }\put(0,-0.3){\sf B }\put(0,3.3){\sf A}\put(2,-0.5){\sf 8\: cm }\put(-1,1.5){\sf 6\: cm }\put(2,2){\sf 10\: cm }\put(0.2,0){\line(0,1){0.2}}\put(0.2,0.2){\line(-1,0){0.2}}\end{picture}](https://img.qammunity.org/2022/formulas/mathematics/high-school/mx4ag7u20iivw118hla8wosfzlg00oup5i.png)