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Please help me!

The Farmer's Ranch House
9. The farmer's house is shown in the diagram below. He wants to build a screened-in patio on the back of his house.
Use the figure to answer the questions. (6 points)
a The area of the patio is planned to be (x + 10x - 200) square feet. What will the length be?
Patio
Patio
**10) - 0-10)
Original
House
b.
What is the area of the original house in simplest form?
Terigth
c
The farmer decides to extend the width of the patio. The area of the patio with the extension is now (x2 + 12x-160) square feet. By how
many feet will the patio be extended from what you found in part a?

Please help me! The Farmer's Ranch House 9. The farmer's house is shown in the diagram-example-1
User Mikkelbreum
by
2.5k points

1 Answer

18 votes
18 votes

Answer:

The answer is below

Explanation:

a) The patio is in the form of a rectangle. The patio has a width of (x - 10) ft. Therefore given that the area of the patio is x² + 10x - 200, hence:


Area=length*breadth\\\\x^2+10x-200=length*(x -10)\\\\x^2+20x-10x-200=length*(x -10)\\\\x(x+20)-10(x+20)=length*(x -10)\\\\(x-10)(x+20)=length*(x -10)\\\\length=x +20

b) Area of original house = length of house * breadth of house

The length of house = length of patio = x + 20; breadth of house = x + 10; therefore:

Area of original house = (x + 20)(x + 10) = x² + 10x + 20x + 200

Area of original house = x² + 30x + 200

c) If the width is extended, hence:


Area=length*breadth\\\\x^2+12x-160=(x+20)*width\\\\x^2+20x-8x-160=(x+20)*width\\\\x(x+20)-8(x+20)=(x+20)*width\\\\(x-8)(x+20)=(x+20)*width\\\\width=x-8\\\\Extended \ width=(x-8)-(x-10)\\\\Extended \ width=2\ feet

User Darren Stone
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3.6k points