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25 votes
25 votes
A boy im50kg at rest on a skateboard is pushed by another boy who exerts a force of 200 N on him. If the first boy's

final velocity is 8 m/s, what was the contact time?
seconds

User Rohan Sanap
by
3.0k points

1 Answer

24 votes
24 votes

Answer:

Time, t = 2 seconds

Step-by-step explanation:

Given the following data;

Mass, m = 50 kg

Initial velocity, u = 0 m/s (since it's starting from rest).

Final velocity, v = 8 m/s

Force, F = 200 N

To find the time, we would use the following formula;


F = \frac {m(v - u)}{t}

Making time, t the subject of formula, we have;


t = \frac {m(v - u)}{F}

Substituting into the formula, we have;


t = \frac {50(8 - 0)}{200}


t = \frac {50*(8)}{200}


t = \frac {400}{200}

Time, t = 2 seconds

User Sir Neuman
by
2.5k points