Answer: 45 degrees
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Work Shown:
We can apply the law of cosines
a^2 = b^2+c^2-2*b*c*cos(A)
(sqrt(5))^2 = (sqrt(2))^2+(3)^2-2*(sqrt(2))*(3)*cos(A)
5 = 2+9-6*(sqrt(2))*cos(A)
5 = 11-6*(sqrt(2))*cos(A)
11-6*(sqrt(2))*cos(A) = 5
-6*(sqrt(2))*cos(A) = 5-11
-6*(sqrt(2))*cos(A) = -6
(sqrt(2))*cos(A) = -6/(-6)
(sqrt(2))*cos(A) = 1
cos(A) = 1/(sqrt(2))
cos(A) = sqrt(2)/2
A = 45 degrees
Use the unit circle for the last step.
Interestingly, this triangle has only one angle that is a whole number. The other two angles are approximate decimal values.