Answer:
Use of the "range" formula will greatly simplify this -
R = V^2 sin 2 θ / g
R = 15^2 sin 70 / 9.8 = 21.6 m distance originally traveled
r = 21.6 /2 = 10.8 if distance is halved
sin 2 θ = 10.8 * 9.8 / 225 = 28.1 deg
θ = 14 deg
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