Answer:
y=3x(x+1)(x-2)=3x^3-3x^2-6x
Explanation:
The polynomial function can be written in the form:
y=a(x-x1)(x-x2)(x-x3)
where
x1=-1
x2=0
x3=2
Therefore
y=a(x+1)(x-0)(x-2)=a(x^2+x)(x-2)=a(x^3-x^2-2x)
To find the value for "a" we use the info about the line passing in (1,-6):
-6=a(1-1-2)
a=3
y=3x(x+1)(x-2)=3x^3-3x^2-6x