Question

Find the product. (Do not use spaces in your answer.)

d j · d k

Answer 1

`\huge\boxed{d^j\cdot d^k=d^(j+k)}`

Explanation:

Use the theorem:

`a^n\cdot a^m=a^(n+m)`

Why? Look at this example:

`2^3\cdot2^4=\underbrace{2\cdot2\cdot2}_(3)\cdot\underbrace{2\cdot2\cdot2\cdot2}_4=\underbrace{2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2}_(7)=2^7`

Therefore

`d^j\cdot d^k=d^(j+k)`

Answer 2

`\displaystyle d^(j + k)`

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Exponential Rule [Multiplying]:
  `\displaystyle b^m \cdot b^n = b^(m + n)`

Explanation:

Step 1: Define

Identify

`\displaystyle d^j \cdot d^k`

Step 2: Find

1. Multiply [Exponential Rule - Multiplying]:
   `\displaystyle d^j \cdot d^k = d^(j + k)`