Question

identify an equation in point slope-slope form for the line perpendicular to y=3 x+5 that passes through(4,-1)

Answer 1

Perpendicular lines have slope that are negative reciprocals.

The slope of the perpendicular line is M = -1/3.

Explanation:

(4,-1) --> X = 4, Y = -1, M = -1/3

y = Mx + b

-1 = (-1/3)*4 + b

-1 = (-4/3) + b

-3/3 = (-4/3) + b

-3 = -4 + 3b

1 = 3b

b = 1/3

y = (-1/3)X + 1/3