Question

A jar contains 38 red marbles numbered 1 to 38 and 38 blue marbles numbered 1 to 38 a marble is drawn at random from the jar

Answer 1

`P(Red) = 0.50`'

`P(Odd) = 0.50\\`

Explanation:

Given

`Red = 38`

`Blue = 38`

Required (Missing part of the question)

(a) The marble is red. (b) The marble is odd-numbered

Solving (a): Probability of Red.

This is calculated as:

`P(Red) = (Red)/(Total)`

`P(Red) = (38)/(38+38)`

`P(Red) = (38)/(76)`

`P(Red) = 0.50`

Solving (b): Probability of Odd

Since each marble type is numbered 1 to 38, then half of it are odd.

i.e. 19 odd numbered red marbles and 19 odd numbered blue marbles.

So, the probability of odd is:

`P(Odd) = (Odd)/(Total)`

`P(Odd) = (19+19)/(38+38)`

`P(Odd) = (38)/(76)`

`P(Odd) = 0.50\\`