346,654 views
2 votes
2 votes
Water is pumped steadily through a 0.10-m diameter pipe from one closed pressurized tank to another tank. The pump adds 4.0 kW of energy to the water and the head loss of the flow is 10 m. Determine the velocity of the water leaving the pump and discharging into tank B.

User Thallius
by
2.4k points

1 Answer

11 votes
11 votes

Complete Question

Complete Question is attached below.

Answer:


V'=5m/s

Step-by-step explanation:

From the question we are told that:

Diameter
d=0.10m

Power
P=4.0kW

Head loss
\mu=10m


(P_1)/(\rho g)+(V_1^2)/(2g)+Z_1+H_m=(P_2)/(\rho g)+(V_2^2)/(2g)+Z_2+\mu


(300*10^3)/(\rho g)+35+Hm=(500*10^3)/(\rho g)+15+10


H_m=((200*10^3)/(1000*9.8)-10)


H_m=10.39m

Generally the equation for Power is mathematically given by


P=\rho gQH_m

Therefore


Q=(P)/(\rho g H_m)


Q=(4*10^4)/(1000*9.81*10.9)


Q=0.03935m^3/sec

Since


Q=AV'

Where


A=\pi r^2\\A=3.142 (0.05)^2


A=7.85*10^(-3)

Therefore


V'=(0.03935m^3/sec)/(7.85*10^(-3))


V'=5m/s

Water is pumped steadily through a 0.10-m diameter pipe from one closed pressurized-example-1
User AmitW
by
3.1k points