Question

Two particles have positions at time t given by s1=4t-t^2 and s2=5t^2-t^3. Find the velocities

Answer 1

Explanation:

Given that,

The positions of the first particle,
`s_1=4t-t^2`

Velocity,

`v_1=(ds_1)/(dt)\\\\v_1=(d(4t-t^2))/(dt)\\\\v_1=4-2t`

Position,

`s_2=5t^2-t^3`

`v_2=(ds_2)/(dt)\\\\v_2=(d(5t^2-t^3))/(dt)\\\\v_2=10t-3t^2`

Hence, this is the required solution.