Question

`\text{Solve for 'x'.}\\\\x^2-25=0\\\\\text{Thank you.}`

Answer 1

Hi there!

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I believe your answer is:

`x = \pm 5`

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Here’s why:

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`\boxed{\text{Solving for 'x'...}}\\\\x^2-25 = 0\\-------------\\\rightarrow x^2 -25 + 25 = 0 + 25\\\\\rightarrow x^2 = 25\\\\\rightarrow √(x^2)=√(25)\\\\\rightarrow \boxed{x = \pm 5}`

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Hope this helps you. I apologize if it’s incorrect.

Answer 2

`x = 5 \: \: \: or \: \: \: x = - 5`

Explanation:

`{x}^(2) - 25 = 0 \\ {x}^(2) - {5}^(2) \\ ( x - 5)(x + 5) = 0 \\ \\ x - 5 = 0 \\ x = 5 \\ or \\ x + 5 = 0 \\ x = - 5`