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The solutions to the equation 2x^2 + x - 1 = 2 are x = -3/2 or x = _______.

The solutions to the equation 2x^2 + x - 1 = 2 are x = -3/2 or x = _______.-example-1
User Yumarx Polanco
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1 Answer

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17 votes

Answer:

The remaining solution to the equation is x = 1

Explanation:

2x^2 + x - 1 = 2

First set the equation to zero by subtracting 2 from each side:

2x^2 + x - 1 - 2 = 2 - 2

2x^2 + x - 3 = 0

Factor the left side of the equation:

2x^2 + x - 3 = 0

(2x + 3)(x - 1) = 0

Now set each factor to zero and solve:

2x+ 3 = 0

2x+ 3 - 3 = 0 - 3

2x= -3

2x/2= -3/2

x= -3/2 (The given expression)

x - 1 = 0

x - 1 + 1 = 0 + 1

x = 1

Since we already knew x = -3/2, the missing solution is x = 1.

User Jahir
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