Question

What volume (mL) of the sweetened tea described in Example 1 contains the same amount of sugar (mol) as 10 mL of the soft drink in this example

Answer 1

The question is incomplete, the complete question is:

What volume (mL) of the sweetened tea described in Example 3.14 contains the same amount of sugar (mol) as 10 mL of the soft drink in this example. The example is attached below.

Answer: 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

Step-by-step explanation:

We first calculate the number of moles of soft drink in a volume of 10 mL

The formula used to calculate molarity:

`\text{Molarity of solution}=\frac{\text{Moles of solute}* 1000}{\text{Volume of solution (mL)}}` .....(1)

Taking the concentration of soft drink from the example be = 0.375 M

Volume of solution = 10 mL

Putting values in equation 1, we get:

`0.375=\frac{\text{Moles of sugar in soft drink}* 1000}{10}\\\\\text{Moles of sugar in soft drink}=(0.375* 10)/(1000)=0.00375mol`

Calculating volume of sweetened tea:

Moles of sugar = 0.00375 mol

Molarity of sweetened tea = 0.05 M

Putting values in equation 1, we get:

`0.05=\frac{0.00375* 1000}{\text{Volume of sweetened tea}}\\\\\text{Volume of sweetened tea}=(0.00375* 1000)/(0.05)=75mL`

Hence, 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink