Question

Need help pleaseee,question is in the pic​

Answer 1

Step-by-step explanation:

For engine 1,

Energy removed = 239 J

Energy added = 567 J

`\eta_1=(239)/(567)\cdot100=42.15\%`

For engine 2,

Energy removed = 457 J

Energy added = 789 J

`\eta_2=(457)/(789)\cdot100=57.92\%`

For engine 3,

Energy removed = 422 J

Energy added = 1038 J

`\eta_3=(422)/(1038)\cdot100=40.65\%`

So, the engine 2 has the highest thermal efficiency.