Question

1.25 X 10^24 molecules of chlorine gas react with sodium to form how many grams of sodium

chloride?
2Na + Cl2
--> 2NaCl

Answer 1

241.28 g NaCl(s)

Step-by-step explanation:

Given 1.25 x 10²⁴ molecules of Cl₂ = 1.25 x 10²⁴molecules Cl₂(g)/6.023 x 10²³ molecules/mole = 2.08 mole Cl₂(g)

2Na(s) + Cl₂(g) => 2NaCl(s)

excess 2.08mole ? mole

∴moles NaCl(s) formed from 2.08 moles Cl₂(g) = 2(2.08 mole NaCl(s))

= 4.16 mole NaCl(g) = 4.16 mole NaCl(s) x 58 g NaCl(s)/mole NaCl(s) = 241.28 g NaCl(s)