Hello,
h(x)=x²+1
k(x)=x-2
First of all, you must understand that:
(h+k)(x)=h(x)+k(x)
So, (h+k)(3)=h(3)+k(3)=(3²+1)+(3-2)=(9+1)+1=11
3h(2)+2k(3)=3*(2²+1)+2*(3-2)
=3*(4+1)+2*1
=15+2
=17
Answer:
3x2-3x+9
Explanation:
(h-k)(3)
(X2+1-(x-2))(3)
(x2+1-x+2)(3)
3x2+3-3x+6
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