Question

A negative charge of -3.0 x 10^-5 C is placed 0.35 m from a positive charge of 9.0 x 10^-5 C. What is the force between the two charges

Answer 1

the force between the two charges is 198.37 N

Step-by-step explanation:

Given;

charge of the first particle, Q₁ = -3 x 10⁻⁵ C

charge of the second particle, Q₂ = 9.0 x 10⁻⁵ C

distance between the two charges, r = 0.35 m

The force between the two charges is calculated from Coulomb's law;

`F = (kQ_1Q_2)/(r^2)`

where k is Coulomb's constant = 9 x 10⁹ Nm²/C²

`F = ((9* 10^9)(3.0* 10^(-5))(9*10^(-5) ))/(0.35^2) \\\\F = 198.37 \ N`

Therefore, the force between the two charges is 198.37 N