Answer:
The value of (2x-2y)^2 is 132.
Explanation:
We know that (2x-2y)^2 = 4(x^2 + y^2 - 2xy)
We can substitute the given values of x^2 + y^2 and xy into the equation above to get:
(2x-2y)^2 = 4(45 - 2*12) = 132
Therefore, the value of (2x-2y)^2 is 132.