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Given x square + y square = 45 and xy=12, find the value of (2x-2y)square

User Adi Fatol
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Answer:

The value of (2x-2y)^2 is 132.

Explanation:

We know that (2x-2y)^2 = 4(x^2 + y^2 - 2xy)

We can substitute the given values of x^2 + y^2 and xy into the equation above to get:

(2x-2y)^2 = 4(45 - 2*12) = 132

Therefore, the value of (2x-2y)^2 is 132.

User Burjua
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