Question

Wright an equation in standard form of the line that passes through (7,-3)and has a slope of 4

Hurry I need it in the next 10 min

Answer 1

Explanation:

We have (y - (-3)) = 4(x - 7).

=> y + 3 = 4x - 28

=> y = 4x - 31

=> 4x - y = 31.

Answer 2

`\sf 4x - y = 31`

Explanation:

In order to find the equation of the line in standard form, we can use the following formula:

Ax + By + C = 0

where A, B, and C are real numbers, and A and B are not both zero.

We can use the point-slope form of the equation of a line to find the values of A, B, and C.

The point-slope form of the equation of a line is:

`\sf y - y_1 = m(x - x_1)`

where
`\sf (x_1, y_1) =(7,-3)` is a point on the line and m = 4 is the slope of the line.

In this case, we have:

`\sf y - (-3) = 4(x - 7)`

Open bracket:

`\sf y + 3 = 4x - 28`

Add 28 on both sides:

`\sf y + 3 +28= 4x - 28 +28`

`\sf y + 31= 4x`

Subtract y on both sides:

`\sf y + 31 - y = 4x - y`

`\sf 4x - y = 31`

Therefore, an equation in the standard form of the line is:

`\sf 4x - y = 31`