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HELP MATHS perpendicular lines

HELP MATHS perpendicular lines-example-1
User AndyPook
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1 Answer

5 votes

Answer:

y =
(1)/(3) x + 4

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given the equation of line L₁

y = - 3x + 8 ← in slope- intercept form

with slope m = - 3

given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = - (
(1)/(-3) ) =
(1)/(3) , then

y =
(1)/(3) x + c ← is the partial equation of line L₂

to find c , substitute the point P(3, 5 ) into the partial equation

5 =
(1)/(3) (3) + c = 1 + c ( subtract 1 from both sides )

4 = c

y =
(1)/(3) x + 4 ← equation of line L₂

User Maulik Hirani
by
8.0k points

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