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35 votes
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A gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. When 7950 kcal of heat is added to the gas, the volume is observed to increase slowly from 12.8 m^3 to 19.4 m^3.

Required:
a. Calculate the work done by the gas. Express your answer with the appropriate units.
b. Calculate the change in internal energy of the gas, Express your answer with the appropriate units.

User Firouziam
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1 Answer

4 votes
4 votes

Answer:

Step-by-step explanation:

From the question we are told that:

Energy
Q=7950kcal=3.3*10^7

Initial Volume
V_1=12.8 m^2

Final Volume
V_2=19.4 m^2

a)

Generally the equation for Work done is mathematically given by


W=P \triangle V

Where


P= Pressure at 1atm

Therefore


W=(1.01*10^5)(19.4-12.8)


W=6.67*10^5J

a)

Generally the equation for Change in internal energy of the gas is mathematically given by


\triangle U=Q-W


\triangle U=3.3*10^7-6.67*10^5J


\triangle U=3.2*10^7J

User Van Amburg
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2.8k points