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10 votes
10 votes
Five children have to form a queue. In how many different ways can they be arranged?

A. 120
B. 100
C. 60
D. 80

User Jeremy Roy
by
2.6k points

1 Answer

12 votes
12 votes

Answer:

120 different ways

The total number of ways to do this is the product because of the fundamental counting principle[1]. So 5x4x3x2x1 = 5! (read as “5 factorial”[2]) = 120 different ways to line up those 5 people. Five people lining up essentially means 5 people sorting into 5 positions.

User Kortina
by
2.3k points
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