Answer:
the 0.10 m C₁₂H₂₂O₁₁ (sugar) solution should have the lowest vapor pressure.
Step-by-step explanation:
The solution with the lowest vapor pressure would be the one with the highest concentration of solute particles. This is because vapor pressure is inversely proportional to the concentration of solute particles in a solution.
In this case, we have four solutions:
1. 0.10 m C₁₂H₂₂O₁₁: This is a solution of sugar (sucrose). It is a non-electrolyte, meaning it does not dissociate into ions when dissolved in water. Therefore, it will have the lowest vapor pressure among the given options.
2. 0.10 m KNO₃: This is a solution of potassium nitrate. It is an electrolyte and will dissociate into potassium ions (K⁺) and nitrate ions (NO₃⁻) when dissolved in water. The presence of more solute particles (ions) will increase the vapor pressure compared to the sugar solution.
3. 0.10 m CaCl₂: This is a solution of calcium chloride. It is also an electrolyte and will dissociate into calcium ions (Ca²⁺) and chloride ions (Cl⁻) when dissolved in water. Like the potassium nitrate solution, it will have a higher vapor pressure than the sugar solution due to the presence of more solute particles.
4. 0.10 M LiPO: This is a solution of lithium phosphate. It is an electrolyte and will dissociate into lithium ions (Li⁺) and phosphate ions (PO₄³⁻) when dissolved in water. Similar to the previous two solutions, it will have a higher vapor pressure compared to the sugar solution.