Question

An object with a mass of 1.5 kg changes its velocity from +15 m/s to +22 m/s during a time interval of 3.5 seconds. What impulse was delivered to the object? 3.0 N • s 11 N • s 25 N • s 56 N • s

Answer 1

11 Ns

Step-by-step explanation:

Impulse = change in momentum

J = Δp

J = mΔv

J = (1.5 kg) (22 m/s − 15 m/s)

J = 10.5 kg m/s

Rounded to two significant figures, the impulse is 11 Ns.

Answer 2

Answer: The impulse delivered to the object is 33 N • s.

Explanation: Impulse = Change in momentum

The momentum of an object is calculated by multiplying its mass by its velocity:

Momentum = Mass x Velocity

Given:

Mass of the object = 1.5 kg

Initial velocity = +15 m/s

Final velocity = +22 m/s

Time interval = 3.5 seconds

First, we need to calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum

To find the initial momentum, we multiply the mass by the initial velocity:

Initial momentum = Mass x Initial velocity

Initial momentum = 1.5 kg x 15 m/s

To find the final momentum, we multiply the mass by the final velocity:

Final momentum = Mass x Final velocity

Final momentum = 1.5 kg x 22 m/s

Now, we can calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum

Change in momentum = (1.5 kg x 22 m/s) - (1.5 kg x 15 m/s)

Simplifying the equation:

Change in momentum = 33 kg m/s

Finally, we have found the change in momentum, which is equal to the impulse delivered to the object. Therefore, the impulse delivered to the object is 33 N • s.