Question

Bobby is buying gumballs for 7 of his friends. There are 51 gumballs before Bobby makes his purchase at the store. Bobby wants to give each of his friends the same amount of gumballs and not have any gumballs left. Which of the following approaches can Bobby use to find the greatest number of gumballs he can purchase to give his friends? A. Divide 51 by 7 -This will show how many each friend receives and the remainder, but not the total number purchased. B. Create a table where one side of the table represents the number of gumballs and the other side represents the number of friends. C. On a piece of paper draw 51 gumballs, circle groups of 7 gumballs, and then count how many gumballs are left not circled. D. Make a list of the multiples of 7 and then purchase the highest multiple of 7 that is less than 51.

Answer 1

In this case, he could purchase 49 gumballs, which would allow each friend to receive 7 gumballs and leaves no leftovers.

Step-by-step explanation:

The subject of this problem is mathematics, specifically division and multiples. Bobby wants to buy gumballs for his 7 friends in such a manner that he is left with no extras. To figure out the maximum number of gumballs he can purchase, he should use approach D: Make a list of the multiples of 7 and then purchase the highest multiple of 7 that is less than 51. In this case, the highest multiple of 7 less than 51 is 49 (7*7=49). This way, each friend gets 7 (49/7=7) gumballs and no gumballs will be left over.
Bobby could also use approach A: Divide 51 by 7 but that will give him a remainder (remainder is 2), which means he will be left with some gumballs. Approaches B and C are also valid but approach D provides the most straightforward answer.Therefore, the best approach would be to use multiples of 7 and purchase 49 gumballs so that each friend gets 7 gumballs and there are no leftovers.

Learn more about Division and Multiples