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A 12- V battery powers a series circuit that contains two lightbulbs. The voltage across one of the lightbulbs is 8 V. What fractional part of the circuits total energy is transformed in the second lightbulb?

User Jonny Five
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1 Answer

6 votes

Answer:

1/3

Explanation:

12-8=4

4/12 = 1/3

User DragoRaptor
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