Question

Complete the table of values:

Answer 1

-3 -2 -1 0 1 2 3

6 0 -4 -6 -6 -4 0

Explanation:

One is given the following function;

`y=x^2-x-6`

The problem asks one to evaluate the function for certain values, substitute these values in place of the variable (x) and simplify to evaluate the function.

`-2\\\\(-2)^2-(-2)-6\\=4-(-2)-6\\=4+2-6\\=6-6\\=0`

`-1\\\\(-1)^2-(-1)-6\\=1-(-1)-6\\=1+1-6\\=2-6\\=-4`

`1\\\\(1)^2-(1)-6\\=1-(1)-6\\=1-1-6\\=0-6\\=-6`

`2\\\\(2)^2-(2)-6\\=4-(2)-6\\=4-2-6\\=2-6\\=-4`

`3\\\\(3)^2-(3)-6\\=9-(3)-6\\=9-3-6\\=6-6\\=0`

Answer 2

Formula given:
`y=x^(2) -x-6`

x -3 -2 -1 0 1 2 3

y 6 0 -4 -6 -4 -4 0

when x = -2

`=(-2)^(2) -(-2)-6`

`=0`

when x = -1

`=(-1)^(2) -(-1)-6`

`=-4`

when x = 1

`=(1)^(2) -(1)-6`

`=-6`

when x = 2

`=(2)^(2) -(2)-6`

`=-4`

when x = 3

`=(3)^(2) -(3)-6`

`=0`