Question

Sodium chloride and lead(II) acetate Express your answer as a chemical equation. Identify all of the phases in your answer. Enter NOREACTION if no reaction occurs.2NaCI(aq) + Pb(OAc), (aq)â PbCl2 (s) +2NaOAc(aq)

Answer 1

The chemical equation for the reaction between sodium chloride and lead(II) acetate is 2NaCl(aq) + Pb(OAc)2(aq) --> PbCl2(s) + 2NaOAc(aq). The phases of the substances involved are indicated in the equation.

Step-by-step explanation:

The chemical equation for the reaction between sodium chloride and lead(II) acetate is:

2NaCl(aq) + Pb(OAc)2(aq) --> PbCl2(s) + 2NaOAc(aq)

In this reaction, sodium chloride (NaCl) and lead(II) acetate (Pb(OAc)2) react to form lead(II) chloride (PbCl2) as a solid precipitate and sodium acetate (NaOAc) as an aqueous solution. The phases of the substances involved are indicated in the equation.

Answer 2

The correct chemical equation is:
`\[ 2 \text{NaCl} (aq) + \text{Pb(OAc)}_2 (aq) \rightarrow \text{PbCl}_2 (s) + 2 \text{NaOAc} (aq) \]`

When sodium chloride (NaCl) reacts with lead(II) acetate
`(Pb(OAc)_2)`, a double replacement reaction occurs. The aqueous solution of sodium chloride and lead(II) acetate yields solid lead(II) chloride
`(PbCl_2)` and sodium acetate (NaOAc) in the aqueous phase.

This metathesis reaction showcases the exchange of ions, resulting in the formation of an insoluble product
`(PbCl_2)` that precipitates out. The remaining sodium acetate remains in the aqueous state. The balanced chemical equation is:

`\[ 2 \text{NaCl} (aq) + \text{Pb(OAc)}_2 (aq) \rightarrow \text{PbCl}_2 (s) + 2 \text{NaOAc} (aq) \]`