Final answer:
The chemical equation for the reaction between sodium chloride and lead(II) acetate is 2NaCl(aq) + Pb(OAc)2(aq) --> PbCl2(s) + 2NaOAc(aq). The phases of the substances involved are indicated in the equation.
Step-by-step explanation:
The chemical equation for the reaction between sodium chloride and lead(II) acetate is:
2NaCl(aq) + Pb(OAc)2(aq) --> PbCl2(s) + 2NaOAc(aq)
In this reaction, sodium chloride (NaCl) and lead(II) acetate (Pb(OAc)2) react to form lead(II) chloride (PbCl2) as a solid precipitate and sodium acetate (NaOAc) as an aqueous solution. The phases of the substances involved are indicated in the equation.