Answer:
C
Explanation:
Inequalities of the type | x | ≥ a , have solutions of the form
x ≤ - a OR x ≥ a
Given
3 | x - 1 | ≥ 12 ( divide both sides by 3 )
| x - 1 | ≥ 4
Then
x - 1 ≤ - 4 OR x - 1 ≥ 4
x - 1 ≤ - 4 ( add 1 to both sides )
x ≤ - 3
OR
x - 1 ≥ 4 ( add 1 to both sides )
x≥ 5
solution is x ≤ - 3 or x ≥ 5 → C