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Solve the equation: 3/x + 1 - 1/2 = 2/3x - 1, where x ≠ -1 and 1/3. A. x = 1 B. x = -2 C. x = 2/3 D. x = -3

User Oskarkv
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1 Answer

3 votes

Answer:

Hi

Explanation:

Since i see, you can't write correctly the equation but reading where x ≠ -1 and 1/3 we may suppose it is:


x\\eq -1\ and\ x\\eq (1)/(3) \\(3)/(x+1) -(1)/(2) =(2)/(3x-1) \\\\Commun \ denominator\ for\ the\ left\ member: 2*(x+1)\\\\(2*3)/(2*(x+1)) -(1*(x+1))/(2*(x+1)) =(2)/(3x-1) \\\\\\(2*3-1*(x+1))/(2*(x+1)) =(2)/(3x-1) \ cross\ product\\\\(6-x-1)*(3x-1)=2*2*(x+1)\\\\(5-x)*(3x-1)=4*(x+1)\\\\15x-5-3x^2+x-4x-4=0\\\\-3x^2+12x-9=0\\\\x^2-4x+3=0\\\\x^2-3x-x+3=0\\\\x(x-3)-(x-3)=0\\\\(x-3)(x-1)=0\\\\x=3\ or\ x=1\\

User BadCanyon
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