Question

What volume of sulfur trioxide gas, SO3, has the same number of atoms as 4 L of helium gas at the same temperature and pressure

Answer 1

4 L of sulfur trioxide gas, SO3, has the same number of atoms as 4 L of helium gas at the same temperature and pressure, according to Avogadro's hypothesis.

Step-by-step explanation:

The volume of sulfur trioxide gas, SO3, that has the same number of atoms as 4 L of helium gas at the same temperature and pressure can be determined using Avogadro's hypothesis. This hypothesis states that equal volumes of all gases at the same conditions contain the same number of particles. Hence, if we have 4 L of helium, we would have an equal volume of 4 L of sulfur trioxide gas possessing the same number of gas particles (atoms in the case of helium and molecules for SO3), assuming the temperature and pressure remain constant.

It is important to remember that volume-volume stoichiometry is straightforward due to the fact that 1 mole of any gas at standard temperature and pressure (STP) occupies a volume of 22.4 L. However, since this problem does not specify STP conditions but equal conditions for both gases, their volumes will still be equal regardless of the specific volume occupied by 1 mole at those conditions.

Answer 2

The volume of sulfur trioxide gas, SO₃ that has the same number of atoms as 4 L of helium gas is 4 L

How to calculate the volume of sulfur trioxide gas, SO₃?

First, we shall obtain the mole of helium gas that occupies 4 L. Details below:

22.4 L of helium = 1 mole of helium

Therefore,

4 L of helium = 4 / 22.4

= 0.179 mole of helium

Now, Avogadro's hypothesis, suggest that equal number of mole of substance has the same number of molecules at same pressure and temperature.

Since the mole of sulfur trioxide gas is the same as that of helium (i.e 0.179 mole). Thus, they will occupy same volume i.e

• Mole of heilum = 0.179 mole
• Mole of sulfur trioxide gas = Mole of heilum = 0.179 mole
• Molar volume of gas = 22.4 L
• Volume of sulfur trioxide gas = ?

Volume of sulfur trioxide gas = mole × molar volume

= 0.179 × 22.4

= 4 L