The volume of sulfur trioxide gas, SO₃ that has the same number of atoms as 4 L of helium gas is 4 L
How to calculate the volume of sulfur trioxide gas, SO₃?
First, we shall obtain the mole of helium gas that occupies 4 L. Details below:
22.4 L of helium = 1 mole of helium
Therefore,
4 L of helium = 4 / 22.4
= 0.179 mole of helium
Now, Avogadro's hypothesis, suggest that equal number of mole of substance has the same number of molecules at same pressure and temperature.
Since the mole of sulfur trioxide gas is the same as that of helium (i.e 0.179 mole). Thus, they will occupy same volume i.e
- Mole of heilum = 0.179 mole
- Mole of sulfur trioxide gas = Mole of heilum = 0.179 mole
- Molar volume of gas = 22.4 L
- Volume of sulfur trioxide gas = ?
Volume of sulfur trioxide gas = mole × molar volume
= 0.179 × 22.4
= 4 L