The first question has 1.93 x 10^25 atoms in 32 moles of sulphur using Avogadro's number. The second question, there are about 6.02 x 10^23 atoms in 32 grams of sulphur. The third question, there would be approximately 1.20 x 10^24 atoms in 32 grams of oxygen.
The subject matter refers to the concept of moles, Avogadro's number and the calculation of individual atoms in specific amounts of substances. Avogadro's number, 6.022 x 10²³, denotes the number of atoms or molecules in one mole of any substance. It is a fundamental constant in Chemistry.
So, for the first question: how many individual atoms are there in 32 moles of sulphur? We use Avogadro's number and multiply it by the given moles. That is 32 moles x 6.022 x 10^23 (Avogadro's number), equals to 1.93 x 10^25 atoms (Option 1).
For the second question: how many individual atoms are there in 32 grams of sulphur? Since the molar mass of sulfur is approximately 32 g/mol, one mole of sulfur is about 32 grams. Therefore, 32 grams equals to approximately one mole of sulfur. Thus, there are about 6.02 x 10^23 atoms of sulfur in a 32 grams-sample (Option 3).
Finally, for the third question: How many individual atoms are there in 32 grams of oxygen? As the atomic mass of oxygen is 16 g/mol, and diatomic oxygen (O2) is 32 g/mol. So 32 grams of O2 are one mole of O2 molecules or about two moles of oxygen atoms. So, there are about 2(6.02 x 10^23) = 1.20 x 10^24 atoms of oxygen in 32 grams of O2 (Option 4).
Learn more about Mole Conversion