Question

PLEASE HELP

A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 10 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground. Give your answer to the nearest hundredth. (1 point)

Answer 1

u should told me earlier what my option r but here To interpret the quotient describing the rate of change in the squirrel's height above the ground, you can calculate the average velocity.

Average Velocity = (Change in Height) / (Change in Time)

Change in Height = Initial Height - Final Height = 10 feet - 0 feet (since the squirrel reaches the ground) = 10 feet

Change in Time = 5.25 seconds

Average Velocity = 10 feet / 5.25 seconds ≈ 1.90 feet per second

So, the rate of change in the squirrel's height above the ground is approximately 1.90 feet per second, which can be rounded to 1.90 to the nearest hundredth.

so the answer would be 1.90 feet

Explanation: