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In a game of bridge, the 52 cards of a conventional pack are distributed at random be- tween the four players in such a way that each player receives 13 cards. Show that the probability that each player receives one ace is 24.48!. 13⁴/52! = 0.105

User Sonida
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The question is to show that the probability that each of the four players in a game of bridge receives one ace is24 • 48! • 134
52!
My explanation so far is that there are 4! ways to arrange the 4 aces, 48! ways to arrange the other cards, and since each arrangement is equally likely we divide by 52!. I believe the 134 represents the number of arrangements to distribute 4 aces among 13 cards, but I don't see why we must multiply by this value as well?
User Hustljian
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Answer:

m

Explanation:

User Niba
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