Question

Challenge  The price of Stock A at 9 A.M. was ​$.15.98 Since​ then, the price has been increasing at the rate of ​$0.08 each hour. At noon the price of Stock B was ​$. 16.48It begins to decrease at the rate of ​$0.11 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

Answer 1

To find out in how many hours the prices of the two stocks will be the same, we can set up an equation to represent the situation.

Let "t" be the number of hours since 9 A.M. (the time Stock A's price started increasing).

The price of Stock A increases by $0.08 per hour, so its price at any time "t" can be represented as:

Price of Stock A = $15.98 + ($0.08 * t)

The price of Stock B decreases by $0.11 per hour, so its price at any time "t" can be represented as:

Price of Stock B = $16.48 - ($0.11 * t)

To find the time when the prices of the two stocks will be the same, we can set these two expressions equal to each other and solve for "t":

$15.98 + ($0.08 * t) = $16.48 - ($0.11 * t)

Now, solve for "t":

$0.08t + $0.11t = $16.48 - $15.98

Combine like terms:

$0.19t = $0.50

Now, divide by $0.19 to isolate "t":

t = $0.50 / $0.19

t ≈ 2.63 hours

So, it will take approximately 2.63 hours for the prices of the two stocks, A and B, to be the same. Since we're dealing with time, it's important to note that this means around 2 hours and 38 minutes.

Explanation:

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