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Jorge has $300 in his savings account at the start of the summer. He wants to have atleast $150 in his account by the end of summer. He plans to withdraw $15 from his account each week for food, clothes and entertainment. Write an inequality that shows how many weeks jorge can withdraw $15 from his account and still remain within the goal he set.

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Let's denote the number of weeks Jorge can withdraw $15 from his account as "w."

At the start of the summer, he has $300 in his account. Each week, he withdraws $15. So, his account balance after w weeks will be:

Initial balance - Total withdrawals = $300 - ($15 * w)

Jorge wants to have at least $150 in his account by the end of the summer. Therefore, we can write the inequality as:

Initial balance - Total withdrawals ≥ $150

$300 - ($15 * w) ≥ $150

Now, you can solve this inequality for w:

$300 - ($15 * w) ≥ $150

Subtract $300 from both sides:

-$15 * w ≥ $150 - $300

-$15 * w ≥ -$150

Now, divide both sides by -15 (remember that when dividing or multiplying by a negative number, you need to reverse the inequality):

w ≤ (-$150) / (-$15)

w ≤ 10

So, the inequality that shows how many weeks Jorge can withdraw $15 from his account and still remain within the goal is:

w ≤ 10

Jorge can withdraw $15 for a maximum of 10 weeks and still have at least $150 in his account by the end of the summer.
User Piotr Pasieka
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