Question

Hello, please I bed urgent help with this math problem please

Answer 1

Option C

Explanation:

Quadratic formula:

`4c^(2) +7c-5=0`

`a=4\\b=7\\x=-5`

`c=\frac{-b\frac{+}{} √(b^2-4ax)}{2a}`

`c=\frac{-7\frac{+}{}49-(4*4*-5) }{2*4}`

`c=\frac{-7\frac{+}{}√(129) }{8}`

hope this helps....

Answer 2

option C

Explanation:

`4c^2 + 7c - 5 = 0 , \ where \ a = 4 , \ b = 7 , \ x = - 5`

`c = (- b \pm √(b^2 - 4ax ))/(2a) \\\\c = (- 7 \pm √(49 - ( 4 * 4 * - 5 )))/(2 * 4) \\\\c = (- 7 \pm √(49 + 80))/(8) \\\\c = (- 7 \pm √(49 + 80))/(8) \\\\c = (- 7 \pm √(129))/(8) \\\\`