Question

While getting on the highway a car accelerates at 5.6 m/s2 for 8.6 sec. getting to a final velocity of 43 m/s. How far did the car travel in that amount of time?

Answer 1

Answer/ Explanation: To determine how far the car traveled in the given amount of time, we can use the equation of motion:

distance = initial velocity * time + 0.5 * acceleration * time^2

Let's break it down step by step:

1. Identify the given information:

- Initial velocity (u) = 0 m/s (since the car starts from rest when getting on the highway)

- Acceleration (a) = 5.6 m/s^2

- Time (t) = 8.6 s

- Final velocity (v) = 43 m/s

2. Calculate the distance:

Using the equation of motion, we can substitute the given values into the formula:

distance = (0 * 8.6) + (0.5 * 5.6 * 8.6^2)

Simplifying the equation:

distance = 0 + (0.5 * 5.6 * 73.96)

distance = 0 + (20.72 * 73.96)

distance ≈ 1,531.47 meters

Therefore, the car traveled approximately 1,531.47 meters in that amount of time.