Question

Clara, Dean and Elaine were candidate in an election in which 1000 people voted.elaine won the election receiving 95 more votes than Dean,and 186 more than Clara. how many votes did dean receive?​

Answer 1

E = 427 votes

Explanation:

• Let Elaine's vote be E
• Let Dean's vote be D
• Let Clara's vote be C.

Translating the word problem into an algebraic expression, we have;

E = D + 95

E = C + 186

Equating the two equations, we have;

D + 95 = C + 186

D = C + 186 - 95

D = C + 91

Also, the sum of all the votes is equal to 1000.

E + D + C = 1000

Substituting the value of "D" we have;

E + (C + 91) + C = 1000

E + C + 91 + C = 1000

E + 2C + 91 = 1000

E + 2C = 1000 - 91

E + 2C = 909

But, E = C + 186

Substituting the value of "E" we have;

(C + 186) + 2C = 909

C + 186 + 2C = 909

3C + 186 = 909

3C = 909 - 186

3C = 723

C = 723/3

C = 241 votes

Next, we would find Elaine's vote;

E = C + 186

E = 241 + 186

E = 427 votes

Lastly, we would find Dean's vote;

E = D + 95

427 = D + 95

D = 427 - 95

D = 332 votes

Check:

E + D + C = 1000

427 + 332 + 241 = 1000

1000 = 1000