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Find the input value for the ordered pair (X, -22) if it is a point on the line with (-12, 6) and the line has a slope of m = 5/4

User Varuni N R
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1 Answer

3 votes

Answer:

So, the input value for the ordered pair
\((X, -22)\)on the line with a slope of
\(m = (5)/(4)\) is \(X = -(172)/(5)\).

Explanation:

To find the input value (X) for the ordered pair (X, -22) if it is a point on the line with (-12, 6) and the line has a slope of
\(m = (5)/(4)\), you can use the point-slope form of a linear equation:


\(y - y_1 = m(x - x_1)\)

Where:


\(m\)is the slope,


\((x_1, y_1)\)is a point on the line.

In this case, you have the point
\((-12, 6)\)and the slope
\(m = (5)/(4)\). You also have the point
\((X, -22)\), which you want to find.

Now, plug in the known values into the point-slope equation:


\(y - 6 = (5)/(4)(x - (-12))\)

Simplify:


\(y - 6 = (5)/(4)(x + 12)\)

Now, we want to find the input value
\(X\) when the output is -22, so set
\(y\) to -22:


\(-22 - 6 = (5)/(4)(x + 12)\)

Now, solve for
\(x\):


\(-28 = (5)/(4)(x + 12)\)

To get rid of the fraction, multiply both sides by
\((4)/(5)\):


\((4)/(5) \cdot (-28) = x + 12\)


\(-(112)/(5) = x + 12\)

Now, subtract 12 from both sides to isolate
\(x\):


\(x = -(112)/(5) - 12\)

To find
\(x\), you can calculate this expression:


\(x = -(112)/(5) - (60)/(5) = -(172)/(5)\)

So, the input value for the ordered pair
\((X, -22)\)on the line with a slope of
\(m = (5)/(4)\) is \(X = -(172)/(5)\).

User El Hoss
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