Question

Find the value of n in 2^(2n) * 2^3 = 2^9.

Answer 1

n = 3

Explanation:

using the rule of exponents

•
`a^(m)` ×
`a^(n)` =
`a^((m+n))`

given

`2^(2n)` × 2³ =
`2^(9)` , then

`2^((2n+3))` =
`2^(9)`

since the bases on both sides are the same, both 2 , then equate exponents, that is

2n + 3 = 9 ( subtract 3 from both sides )

2n = 6 ( divide both sides by 2 )

n = 3