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Find the value of n in 2^(2n) * 2^3 = 2^9.

1 Answer

2 votes

Answer:

n = 3

Explanation:

using the rule of exponents


a^(m) ×
a^(n) =
a^((m+n))

given


2^(2n) × 2³ =
2^(9) , then


2^((2n+3)) =
2^(9)

since the bases on both sides are the same, both 2 , then equate exponents, that is

2n + 3 = 9 ( subtract 3 from both sides )

2n = 6 ( divide both sides by 2 )

n = 3

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