Question

Find two factors of 108 such that their sum is double their

difference.
108
/ \
□□ □+□=2x[□-□]

Answer 1

the two factors are 6 and 18

Explanation:

the two required factors of 108 = 6 and 18

sum = 6 + 18 = 24

difference = 18 - 6 = 12

double of the difference = 2 * 12 = 24 which is equal to the sum

the two required factors are 6 and 18

108

/ \

6 18 6 + 18 = 2 * (18 - 6)