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The length of a rectangle is 1 cm more than its width and its perimeter is 14 cm, then the area of herectangle is a) 16 cm b) 12 cm c) 48.75 cm d) 10 cm

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Final answer:

By using the given perimeter to formulate and solve an equation, we find that the width of the rectangle is 3 cm and the length is 4 cm. Multiplying these values together, we find that the area of the rectangle is 12 cm2.

Step-by-step explanation:

This is a problem in mathematics dealing with the concept of rectangles and their properties, in particular, perimeter and area. Let's denote the width of the rectangle by x (measured in cm). Therefore the length of the rectangle is x+1 cm.

The perimeter of a rectangle is given by the equation 2*length + 2*width. So, given that the perimeter is 14 cm, we can form the equation 2*(x+1) + 2*x = 14. Solving this equation gives x = 3. So, the width of the rectangle is 3 cm and the length is 4 cm.

The area of a rectangle is calculated by multiplying the length and the width. Hence, the area of this rectangle would be 3 cm * 4 cm = 12 cm2, so the correct answer is b) 12 cm.

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