To find the distance from a point to a plane, we can use the formula:
Distance = |ax + by + cz + d| / sqrt(a^2 + b^2 + c^2)
In this case, the point is (-6, 3, 5) and the equation of the plane is x - 2y - 4z = 8.
Let's substitute the values into the formula:
Distance = |(-6) - 2(3) - 4(5) + 8| / sqrt(1^2 + (-2)^2 + (-4)^2)
Distance = |-6 - 6 - 20 + 8| / sqrt(1 + 4 + 16)
Distance = |-24| / sqrt(21)
Distance = 24 / sqrt(21)
Therefore, the distance from the point (-6, 3, 5) to the plane x - 2y - 4z = 8 is 24 / sqrt(21).