answer:
Let's assume that Wes has x number of quarters and y number of dimes. We can set up two equations to represent the given information.
Equation 1: The total value of quarters and dimes is $11.85.
0.25x + 0.10y = 11.85
Equation 2: The total number of coins is 51.
x + y = 51
To solve this system of equations, we can use the method of substitution or elimination. In this case, let's solve it using the elimination method.
First, let's multiply Equation 2 by -0.10 to make the coefficient of y in Equation 2 equal to -0.10y:
-0.10(x + y) = -0.10(51)
-0.10x - 0.10y = -5.10
Now, we can add Equation 1 and Equation 2:
(0.25x + 0.10y) + (-0.10x - 0.10y) = 11.85 - 5.10
0.15x = 6.75
Dividing both sides of the equation by 0.15:
x = 6.75 / 0.15
x = 45
Now, substitute the value of x back into Equation 2 to find the value of y:
45 + y = 51
y = 51 - 45
y = 6
Therefore, Wes has 45 quarters and 6 dimes.
In summary:
- Number of quarters (x): 45
- Number of dimes (y): 6
Alli <3